Question 230818
Most classroom problems of this type have integer solutions.
The last term is 24, so try 1, 2, 3, 4, 6 until you find one (it could be + or minus).
2 is a solution, so divide by (x-2).
--> x^3 + 5x^2 + 10x + 12
-3 is a solution, divide by (3+3)
--> x^2 + 2x + 4
*[invoke solve_quadratic_equation 1,2,4]