<PRE><B>Question 230844</B>
square root of 12 X square root of 5 = 2X square root of 15 
{{{sqrt(12) * sqrt(5) = 2*sqrt(15)}}}
:
Factor 12 inside the radical to reveal the perfect square (4)
{{{sqrt(4*3) * sqrt(5) = 2*sqrt(15)}}}
:
Extract the square root of 4
{{{2*sqrt(3) * sqrt(5) = 2*sqrt(15)}}}
:
which is
{{{2*sqrt(3*5) = 2*sqrt(15)}}}
:
so you have
{{{2*sqrt(15) = 2*sqrt(15)}}}</PRE>