Question 230805
radical i = a+bi.
{{{sqrt(i) = a+bi}}}
square both sides
{{{i = a^2 - b^2 + 2abi}}}
2ab = 1 --> a = 1/(2b)
a^2 = b^2
1/(4b^2) = b^2
4b^4 = 1
a = b = 1/2
a = b = -1/2 
a = b = 2 complex roots, also