Question 30385
Assuming you mean: {{{ ( 1/(a+1) ) / ( 1/(a^2-1) ) }}}, we get:
{{{ ( 1/(a+1) ) * ( (a^2-1)/1 ) }}}
{{{ (a^2-1)/(a+1) }}}
{{{ ((a-1)(a+1))/(a+1) }}}
{{{ (a-1) }}}


As for the answer you quote, a/(a-1), I cannot see how that was gotten, from the starting point i used.


jon.