Question 230780
Find two consecutive natural numbers,such that one third of the smaller numbers is one more than one fourth of the greater.    
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Let x = first of two consecutive numbers (smaller)
then
x+1 = second of two consecutive numbers (larger)
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(1/3)x = (1/4)(x+1)
Multiplying both sides by 12 (common denominator):
4x = 3(x+1)
4x = 3x+3
x = 3 (smaller number)
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Larger number:
x+1 = 3+1 = 4
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The two consecutive numbers are: 3 and 4