Question 230632
Don is twice as old as Irene; Ed is 16 years older than Irene. The sum of all three of their ages is 60 years. Find the age of each person.


Step 1.  Let x be the age of Irene.


Step 2.  Let 2x be the age of Don since he'1 twice as old as Irene.


Step 3.  Let x+16 be the age of Ed since he's 16 years older than Irene.


Step 4.  Then, x+2x+x+16=60 since the sum of their ages is 60.


Step 5.  Solving yields the following steps


{{{4x+16=60}}}


Subtract 16 from both sides of the equation


{{{4x+16-16=60-16}}}


{{{4x=44}}}


Divide by 4 to both sides of the equation


{{{4x/4=44/4}}}


{{{x=11}}},  {{{2x=22}}}, {{{x+16=27}}}.  Note the sum of the ages equal to 60 years old.


Step 6.  ANSWER:  Irene is 11 years old, Don is 22 years old, and Ed is 27 years old.


I hope the above steps were helpful.


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And good luck in your studies!


Respectfully,
Dr J

http://www.FreedomUniversity.TV