Question 230603
*[Tex \LARGE \frac{b^{-4y+7}b^y}{b}]


*[Tex \LARGE \frac{b^{(-4y+7)+y}}{b}]


*[Tex \LARGE \frac{b^{-3y}}{b}]


*[Tex \LARGE b^{-3y-1}]


Answer: *[Tex \LARGE \frac{b^{-4y+7}b^y}{b}=b^{-3y-1}]