Question 230556
Well first lets assign varables.  Let n be the number of nickles and d be the number of dimes.  Then from the problem we get the following system of equations:<br>

n+d=30
4d=n<br>

now since n is already solved for in the second equation then we can just substitute that into the first equation and solve for d.<br>

n+d=30
4d+d=30
d = 6<br>

now we can substitute that back into the second equation and find n.  <br>

4d=n
4(6)=n
24=n<br>

so we know that Jason has 24 nickles and 6 dimes for a total of $0.6+$1.20 = $1.80.