<PRE><B>Question 230568</B>
The length of a rectangle is 3 feet longer than the width. The perimeter is 30 feet. Find the dimensions of the rectangle.


Step 1.  Perimeter P means adding up all 4 sides of a rectangle.


Step 2.  Let w be the width.


Step 3.  Let w+3 be the length since it is 3 feet longer.


Step 4.  Then, P=w+w+w+3+w+3 or 4w+6=30


Subtract 6 from both sides of the equation


{{{4w+6-6=30-6}}}


{{{4w=24}}}


Divide by 4 to both sides of the equation


{{{4w/4=24/4}}}


{{{w=6}}} and {{{w+3=9}}}.  Note that {{{P=2(6+9)=30}}} which is a true statement.


Step 5.  ANSWER:  The width is 6 feet and the length is 9 feet.


I hope the above steps were helpful.


For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


Good luck in your studies!


Respectfully,
Dr J
</PRE>