Question 230460
Test these terms by replacing x with any number greater than 13/3=4.33.
Try 5
3*5-13=15-13=2 the short side
2*5-1=10-1=9 the second side.
3*5-4=15-4=11 the hypotenuse. 
(3x-13)^2 + (2x-1)^2 = (3x-4)^2
9x^2-78x+169+4x^2-4x+1=9x^2-24x+16
9x^2+4x^2-9x^2-78x-4x+24x+169+1-16=0
4x^2-58x+154=0
(x-11)(4x-14)=0
x-11=0
x=11 ans.
4x-14=0
4x=14
x=14/4
x=3.5 ans.