<PRE><B>Question 230355</B>
*[Tex \LARGE \int \frac{4x-11}{2x^2-11x+19}dx]


Let *[Tex \LARGE u = 2x^2-11x+19 \ \Rightarrow \frac{du}{dx}=4x-11 \ \Rightarrow du=(4x-11)dx]


*[Tex \LARGE =\int \frac{du}{u}]


*[Tex \LARGE =\ln(u)+C]


*[Tex \LARGE =\ln(2x^2-11x+19)+C]


Answer: *[Tex \LARGE \int \frac{4x-11}{2x^2-11x+19}dx=\ln(2x^2-11x+19)+C]
</PRE>