Question 230339
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Actually, that is only true if you start from a position considered to be zero.  Otherwise, a more general function for position as a function of time given constant acceleration is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ s(t)\ =\ \frac{1}{2}at^2\ +\ v_ot\ +\ s_o]


Where *[tex \Large v_o] is the initial velocity and *[tex \Large s_o] is the initial position.


What else did you want to know about this?  By the way, it generally helps with the communication process if you take the time to actually ask a question.  Saves us poor tutors from having to <b>GUESS WHAT IT IS YOU WANT!</b>


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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