Question 230313
Q: f(x) = x^2+4x+4 
Quadratic with a = 1 ; b = 4 ; c = 4
Quadratic Formula: x = [-b +- sqrt(b^2-4ac)]/(2a)
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Use the quadratic formula to determine the x-intercepts (if any) of the following function.
x = [-4 +- sqrt(16 - 4*1*4)]/(2)
x = [-4 +-sqrt(0)]/2
x = -2 + 0 or x = -2 - 0
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The x-intercept is x = -2
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Then evaluate the function for several values of x, and use the resulting points to graph the function.
If x = -5, y = (-5)^2+4*-5+4 = 25-20+4 = 9
If x = -3, y = (-3)^2+4*-3+4 = 1
If x = 0, y = (0)^2+4*0 + 4 = 4
If x = 2, y = (2)^2 + 4*2 + 4 = 16
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Plot the points: (-5,9)(-3,1)(0,4)(2/16) and draw a smooth 
curve thru them:
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{{{graph(400,300,-10,10,-10,10,x^2+4x+4)}}}
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Cheers,
Stan H.