Question 30396
a) Since logarithm's bases are equal they can cancel out:
*[tex log[3]x^2=log[3]4]
*[tex x^2=4]

*[tex x=2]


b)*[tex log(2)(x+2)^2=log(2)(3x+16)]
{{{x^2+4x+4=3x+16}}}
{{{x^2+x-12=0}}}
<pre>Factor: (x+4) or (x-3)
x=-4 or x=3
Remove negative x =3 
<b>Paul.