Question 230168
 i^37
plese explain how to get the answer thank you
------
{{{i = sqrt(-1)}}}
{{{i^2 = -1}}}
{{{i^4 = 1}}}
Since i^4 = 1, any power of i is the remainder of the exponent/4
-------------
37/4 = 9 REM 1
i^37 = i^1 = i