Question 30392
First number = x
Second number = x+8
Equation:

*[tex (x+8)^2=208+x^2]

*[tex x^2+16x+64=208+x^2]
<pre>16x=544
x=34


34+8=42


<font color = blue> Hence, the smaller number is 34 and the larger number is 42.</font>
Paul.