Question 30350
Let x^2 = y

So, y^2 - 6y + 5 = 0
=> (y-5)(y-1) = 0
=> y = 5 or y = 1

Substituting y = x^2,
x^2 = 1 or x^2 = 5
=> x = +1 or x = -1 or x = sqrt(5) or x = - sqrt(5)