<PRE><B>Question 229435</B>
Find b^2 - 4ac and the number of real solutions to each
equation. -3x2 + 7x = 0
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A general quadratic form is ax^2 + bx + c = 0
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Your Problem:
a = -3 ; b = 7 ; c = 0
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So b^2 - 4ac = 7^2 - 4*-3*0 = 7^2 = 49
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Since b^2-4ac is positive the quadratic has two  unequal Real Number solutions.
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Cheers,
Stan H.
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