Question 229329
Simplify; express answer with only positive exponents.
:
square both terms in the denominator
{{{(-x^-4*y^3)/(6y^-2)^2}}} = {{{(-x^-4*y^3)/(6^2*y^(-2*2))}}} = {{{(-x^-4*y^3)/(36*y^-4)}}}
Reciprocal will get rid of the negative exponent
{{{(y^3*y^4)/(36(-x^4))}}} = {{{(y^7)/(-36x^4))}}} = {{{-(y^7)/(36x^4))}}}