Question 229195
Find the x and y intercept points of {{{-3x-2y=12}}}


Step 1.  Intercepts means that the intersect the x or y axis.  This means that one of the coordinates is zero.  So for x=0, then the point (0,b) has b a the y-intercepts. and for y=0, then the point (a,0) has a as the x-intercept.


Step 2.  Then for x=0 in equation{{{-3x-2y=12}}} we have


{{{-3*0-2y=12}}}


{{{-2y=12}}}


Divide by -2 to both sides of the equation


{{{cross(-2)y/cross(-2)=12/-2}}}


{{{y=-6}}} or {{{b=-6}}} 


So we have (0,-6) as one point with b=-6 as the y-intercept.


Step 3.  Then for y=0 in equation{{{-3x-2y=12}}} we have


{{{-3x-2*0=12}}}


{{{-3x=12}}}


Divide by -3 to both sides of the equation


{{{cross(-3)y/cross(-3)=12/-3}}}


{{{y=-4}}} or {{{a=-4}}} 


So we have (-4, 0) as one point with a=-4 as the x-intercept.


Step 4.  ANSWER:   So we have (0,-6) as one point with b=-6 as the y-intercept and we have (-4,0) as one point with a=-4 as the x-intercept.


We can use these two points (-4,0) and (0,-6) to plot the graph.


{{{graph(400,400, -10,10, -10, 10, -3x/2-6)}}}


I hope the above steps were helpful.


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Good luck in your studies!


Respectfully,
Dr J