Question 229230
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Since the dimensions of the cone are given in feet, i.e. 28 feet base diameter and 12 feet height, when you square the radius, in feet, you get feet squared, then when you multiply by height, in feet, you get feet cubed, or cubic feet.  But the problem requires the answer in cubic <u>yards</u>.  3 times 3 times 3 equals 27, so there are


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{3}(3.14)(14)^2(12)\text{ ft^3}]


in this cone, but there are


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\frac{1}{3}(3.14)(14)^2(12)}{27}\text{ yd^3}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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