Question 229176
One number is 13 more than another, and the sum of the smaller number and twice the larger number is 50. Find the two numbers. 
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Equations:
x = y+13
y+2x = 50
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Substitute for "x" and solve for "y":
y + 2(y+13) = 50
y + 2y + 26 = 50
3y = 24
y = 8
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Since x = y + 13, x = 21
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Cheers,
Stan H.