Question 229087
let the 1st number be x
2nd be x+2
3rd be x+4


(x+4+x+2)-x +8= (x+x+2+x+4)
2x+6-x +8 = (3x+6)
x+14= 3x +6
8 = 2x
4 = x


the three even consecutive numbers are 4 , 6 and 8.