Question 228926
Let {{{j}}}= Jose's average speed
In {{{2.1}}} hrs, Jose has traveled
{{{d = 2.1j}}}
Kayla's speed is {{{j + 35}}}
The distance Kayla traveled to catch Jose is
{{{(j + 35)*1.2}}}
Jose traveled {{{(j + 35)*1.2 - 2.1j}}} in 1.2 hrs
Writing 
{{{d = r*t}}},
{{{(j + 35)*1.2 - 2.1j = j*1.2}}}
{{{1.2j + 42 - 2.1j = 1.2j}}}
{{{2.1j = 42}}}
{{{j = 20}}} mi/hr
Jose's average speed is 20 mi/hr 
check answer
In {{{2.1 + 1.2 = 3.3}}} hrs Jose traveled
{{{20*3.3 = 66}}} mi
In 1.2 hrs Kayla traveled
{{{(35 + 20)*1.2 = 66}}} mi
OK