Question 228831
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Let *[tex \Large x] represent Fran's age now.  Then Nancy's age now is *[tex \Large 4x].  Fran's age 3 years ago is *[tex \Large x - 3], and Nancy's age 3 years ago is *[tex \Large 4x - 3].  Three years ago the sum of their ages was 4, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (4x - 3) + (x - 3) = 4]


Solve for *[tex \Large x] and then subtract 3.  You will discover that Fran's mother wasn't even expecting 3 years ago.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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