Question 228547
What is the consecutive number of which 4 over 7 of the sum of first and second
 equals the third numbers decrease by 1?
:
Three consecutive numbers: x, (x+1), (x+2)
:
{{{4/7}}}(x + (x+1)) = (x+2) - 1
{{{4/7}}}(2x+1) = (x + 1)
Multiply both sides by 7
4(2x + 1) = 7(x + 1)
:
8x + 4 = 7x + 7
8x - 7x = 7 - 4
x = 3
;
Numbers are: 3, 4, 5
;
:
See if that works in the statement:
"4/7 of the sum of first and second equals the third numbers decrease by 1"
{{{4/7}}}(3+4) = (5) - 1
{{{4/7}}}(7) = 4
4 = 4