Question 228727
Hint: Recall that if *[Tex \LARGE z_{1}=r_{1}\left(\cos(\theta_{1})+i\sin(\theta_{1})\right)] and *[Tex \LARGE z_{2}=r_{2}\left(\cos(\theta_{2})+i\sin(\theta_{2})\right)], then


*[Tex \LARGE \frac{z_{1}}{z_{2}}=\frac{r_{1}}{r_{2}}\left(\cos(\theta_{1}-\theta_{2})+i\sin(\theta_{1}-\theta_{2})\right)]


Basically, you're dividing the values of 'r' and subtracting the theta values. Once you have a simplified form of *[Tex \LARGE \frac{z_{1}}{z_{2}}], then just convert that to rectangular form.