Question 228686
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Let *[tex \Large x] represent the measure of the longer piece.  Then the measure of the shorter piece must be *[tex \Large 27\ -\ x].  Since these two pieces are in the ratio 4:5, we can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{27-x}{x}\ =\ \frac{4}{5}]


Cross multiply and solve for *[tex \Large x].



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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