Question 228645
((x^2y^6)/(2x^5)) 
Canceling like-term x's:
((y^6)/(2x^3))
((y^2)^3/6(2x^3))
Taking the cube root:
y^2/x * cuberoot(1/2)
Or, this can be written as:
y^2/x * 1/2^(1/3)
Rationalizing:
y^2/x * 1/2^(1/3) * 2^(2/3)/2^(2/3)
y^2/x * 2^(2/3)/2
y^2/x * cuberoot(4)/2
[y^2*cuberoot(4)]/[2x]