Question 228595
Let x= smaller integer
x+2 = larger integer


Twice the larger IS forty less than 3 times smaller
2(x+2) = 3x-40
2x+4 = 3x-40


Subtract 2x from each side:
2x-2x+4 = 3x-2x-40
4=x-40 


Add +40 to each side
4+40=x-40+40
44=x
x=44
x+2 = 46


Check:
Twice the larger is 40 less than 3 times the smaller.
2*46= 3*44-40
92= 132 - 40
It checks!


Dr. Robert J. Rapalje, Retired
Seminole State College
Altamonte Springs Campus