<PRE><B>Question 228526</B>
The perimeter of a rectangular screen is 272 inches. If the length of the screen exceeds twice its width by 10 inches, what is the screen length and width?


Step 1.  Perimeter P means adding up all 4 sides of a rectangle.


Step 2.  Let w be the width.


Step 3.  Let 2w+10 be the length since the length exceeds twice its width by 10 inches


Step 4.  Then, P=w+w+2w+10+2w+10=6w+20=272


Step 5.  Solving yields the following steps:


Subtract 20 from both sides of the equation


{{{6w+20-20=272-20}}}


{{{6w=252}}}


Divide by 6 to both sides of the equation


{{{6w/6=252/6}}}


{{{w=42}}} and {{{2w+10=94}}}.  Then P=2(42+94)=272 which is a true statement.


Step 6.  ANSWER:  The width is 42 inches and the length is 94 inches.


I hope the above steps were helpful.


For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


Good luck in your studies!


Respectfully,
Dr J
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