Question 30287
To solve this first assign variables to your various terms. 

Let n=nickels and let d=dimes

We know that Nickels=5 cents and dimes=10 cents so we can then say that

5n+10d=330

(5 cents times the number of nickels (n) plus 10 cents times the number of dimes (d) is equal to our total number of cents. 330 or $3.30)

we then read in our problem that There are 27 more nickels than dimes. 

We can express this like so (n=d+27) or the number of nickels is equal to the number of dimes plus 27.

Now that we have a term to work with we can plug n=d+27 back into our original equattion.

5n+10d=330

5(d+27)+10d=330

5d+135+10d=330

Combine like terms

15d+135=330

Bring the "135" over the equal sign, its sign reverses and so you will subtract it from 330

15d=330-135

combine like terms

15d=195

divide through by 15

d=13

Number of dimes=13
Number of Nickles=40