Question 228139
Which three consecutive integers have a product that is 800 times their sum?
x*(x+1)*(x+2) = 800*(3x+3)
x^3 + 3x^2 + 2x = 2400x + 2400
x^3 + 3x^2 - 2398x - 2400 = 0
x = -1
Divide by (x+1)
--> x^2 + 2x - 2400 = 0
(x + 50)*(x - 48) = 0
x = 48
x = -50