Question 227068
{{{m^5 + 32x^5}}} 
{{{32 = 2^5}}}
= {{{(m + 2x)*(m^4 - 2m^3x + 4m^2x^2 - 8mx^3 + 16x^4)}}}
---------------
The sum of any two values to an odd power can be factored as above.
The difference can also be factored in a similar manner, when the exponents are odd.