Question 228032
{{{(2y^2+9y-35)/(y+7)}}}

You would do the foil method. (first, outside,inside, last)

{{{(2y-5)(y+7)/(y+7)}}}

For this part, think of what two numbers would multiply to equal 35, but also add up to equal 9. 

So now, you would cross out the {{{y+7}}}

and you're left with {{{2y-5}}}