Question 228018
9X^2 +18x-5

now i divide 9 into 9x^2 , 18x and -5 to get

x^2 + 2x - 5/9  = 0
:
x^2 + 2x + ___ = {{{5/9}}}
:
Complete the square, divide the coefficient of 2 by 2 and square (2/2)^2 = 1 
x^2 + 2x + 1 = {{{5/9}}} + 1; added 1 to both sides
:
x^2 + 2x + 1 = {{{5/9}}} + {{{9/9}}}
:
(x + 1)^2 = {{{14/9}}} 
:
Find the square root of both sides
x + 1 = +/- {{{sqrt(14/9)}}}
:
Extract the square root of 1/9
x + 1 = +/- {{{(1/3)sqrt(14)}}}
:
Two solutions
x = -1 - {{{(1/3)sqrt(14)}}}
and
x = -1 + {{{(1/3)sqrt(14)}}}
;
:
I know this is not what your book says, but that's what I get for this equation
It checked out on my Ti83