Question 227874
In other words, what are all the possible
ways that all 6 can perform while C must
be 3rd and D must be 4th.
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The 1st to perform can't be C or D, but he can
be any one of the others, or {{{4}}} possible
comedians.
The next one can't be C or D, or the one that
just performed, so {{{3}}} possible
Then comes C and D in just {{{1}}} possible
way
The 5th one can be 1 of 2 or {{{2}}} possible
The 6th one has only {{{1}}} choice left
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The number of ways that all 6 can perform is:
{{{4*3*1*2*1 = 24}}} possible ways