Question 227453
f(x)= {{{(5x-3)/(2x+1)}}}
:
y = f(x)
:
y = {{{(5x-3)/(2x+1)}}}
: 
Swap y for x, solve for y
{{{(5y-3)/(2y+1)}}} = x
:
5y - 3 = x(2y + 1); multiply both sides by (2y+1)
:
5y - 3 = 2xy + x; subtract 2 xy from both side
:
5y - 2xy = x + 3; add 3 to both sides
:
y(5 - 2x) = x + 3; divide both sides by (5-2x)
:
y = {{{(x+3)/(5-2x)}}}
:
f-1(x) = {{{(x+3)/(5-2x)}}}