Question 227778
The perimeter of a rectangle is 106 inches. The length exceeds the width by 45 inches. Find the length and the width.


The length is 49 inches.


(Type an integer or a decimal)


Step 1.  The perimeter P means adding up all the four sides of a rectangle.


Step 2.  Let w be the width.


Step 3.  Let w+45 be the length


Step 4.  Then, P=w+w+w+45+w+45=106.


Step 5.  Solving yields the following steps


{{{4w+90=106}}}


Subtract 90 form both sides of the equation


{{{4w+90-90=106-90}}}


{{{4w=16}}}


Divide by 4 to both sides of the equation.


{{{4w/4=16/4}}}


{{{w=4}}}


For {{{w=4}}} , then {{{w+4=49}}} and check {{{P=2(4+49)=106}}} which is a true statement.


Step 6.  ANSWER:  The length is 49 inches.


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J