Question 227638
How do I find the plotting points and the the y-intercept


{{{y=4x/3+2}}}


Step 1.  First to draw this line, we need two points.  Here, are Step-By-Step videos on how to plot the lines:


http://www.freedomuniversity.tv/courses/IntroAlgebra/Module3.html


Step 2.  This equation is in slope-intercept form given as y=mx+b where m is the slope and b is the y-intercept when x=0 or at point (0,b).   So in this example the slope is {{{m=4/3}}} and the y-intercept is {{{b=2}}} when x=0 or at point (0,2).  We have the y-intercept as one point at (0,2).


Step 3.  To plot other points choose a value of x and then find y.  For example, let x=3, then for the equation {{{y=4x/3+2}}} then y=4*3/3+2=6.  So one point is (3, 6).  


Step 4.  Now we have two points (0,2) from Step 2 and (3,6) from Step 3 to draw our line.  The graph of the line using these points is shown below


{{{graph(600,600, -10,10,-10,10, 4x/3+2)}}}.


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J


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