Question 227543
c=3a-8
b=2a+8
a^2+b^2=c^2
a^2+(2a+8)^2=(3a-8)^2
a^2+4a^2+32a+64=9a^2-48a+64
5a^2-9a^2+32a+48a+64-64=0
-4a^2+80a=0
-4a(a-20)=0
a-20=0
a=20 ans.
b=2*20+8=40+8=48  ans.
c=3*20-8=60-8=52 ans.
Proof:
20^2+48^2=52^2
400+2,304=2,704
2,704=2,704