Question 227488

3b+2a=2 (eqn 1)
-2b+a=8 (eqn 2)

from eqn 2; 
a=8+2b
Subst. eqn2 to eqn1


3b+2(8+2b)=2
3b+16+4b=2
7b=2-16
7b=-14
b=-2


since b=-2 ;
a=8+(-2)
a=6