Question 227402
Let {{{P}}} = population on Jan 1, 2005
In a year it will be {{{P + .014P = P*(1.014)}}}
The next year it will be 
{{{P*(1.014) + .014*P*(1.014) = P*(1.014)*(1 + .014)}}}
{{{P*(1.014)*(1 + .014) = P*(1.014)^2}}}
So, the rule is:
{{{P[n] = P*(1.014)^n}}} where {{{n}}} = number of years
since Jan 1, 2005
{{{20025 - 2005 = 20}}}, so
{{{P[20] = P*1.014^20}}}
{{{P[20] = P*1.320562924}}}
{{{P[20] = 6486915022*1.320562924}}}
{{{P[20] = 8566379470}}}