Question 3850
if roots are (4+i) and (4-i), then we can say:


x=(4+i) or x=(4-i)


so, x-(4+i)=0 or x-(4-i)=0



So, the factors are (x-(4+i))(x-(4-i))=0
hence (x-4-i)(x-4+i)=0


Now expand, to give {{{x^2 - 4x + xi - 4x + 16 - 4i - xi + 4i - i^2 = 0}}}
{{{x^2 - 8x + 16 - i^2 = 0}}}
{{{x^2 - 8x + 16 - (-1) = 0}}}
{{{x^2 - 8x + 17 = 0}}}


So, a possible equation is y={{{x^2 - 8x + 17}}}


jon.