Question 227103
Well first we need to factor these expressions as much as possible.  <br>

25c^2 = 5c(5c)
3c^2-18c+27 = 3(c^2-6c+9) = 3(c-3)(c-3)
3c-9 = 3(c-3)<br>

so plugging back in we get:<br>

(25c^2/3c^2-18c+27) * (3c-9/5c) = 5c(5c)/3(c-3)(c-3) * 3(c-3)/5c<br>

Now we simplify as much as we can before we multiply.<br>

the 5c on top can cross with the 5c on bottom.  The 3(c-3) on the bottom can cross with the 3(c-3) on the top.<br>

This will leave us with the final answer of {{{5c/(c-3)}}}