Question 30199
log_3(3) = 1
so we can write,
log_3(x+16) = log_3(3) + log_3(2-x)
log_3(x+16) = log_3(3*(2-x)) = log_3(6-3x)
log_3(x+16) = log_3(6-3x)
x+16 = 6-3x
4x = -10
x = -2.5
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