Question 30193
5x+2y=3............(1)

3x+4y=13............(2)

For elimination we need one variable in both equation to be equal,,,but here we dnt have that,,,so further solution is done in the following ways...

Multiply (1) by  3 and you get ...
15x + 6y = 9............(3)

Multiply (2) by 5 and you get 
15x + 20y = 65............(4)

Now , by elimination method and subtract (4) from (3)and we get...

15x + 6y  = 9............(3)
15x + 20y = 65............(4)
-   -       -
-------------------
     - 14y = -56      (15x in both eqautions would be eliminated)
  or     y = -56/-14
         y = 4

 now, substitute the value of y in any of the equation to get the value of x here I am taking (2)...

3x+4y=13............(2)
putting the values of y = 4 ,,we get

3x + 4 * 4 = 13

3x + 16 = 13

3x = 13 - 16 

3x = -3 

x = -3/3

x = -1

Now if you wanna verify you answer ,,,you can put the values of x and y in any of the equation and if you get LHS=RHS,,,this means that you answer is correct..

hope this will help you 

Please feel free to revert back for any further queries.