Question 30144
Rewrite the equation as 2x~2+3x-20=0.

The factors of 2 are 1&2, the factors of 20 are 1,2,4,5,10,&20.

Because the number is - one number must be = & the other one -.

The combinations or multiplying 1&2 to each set of factors of 20 must have a difference of 3. The only combination is (1x+5)&(2x-4)or 5-8= -3

Therefore the factors are(x-4)x(2x+5). x times 2x=2x~2
                                       -4 times 2x=-8x
                                       x times 5=5x
                                       -4 times 5=20
2x~2-8x+5x-20=0
2x~2-3x-20=0