Question 226515
Let x=first consecutive even integer, x+2=second consecutive consecutive integer, x+4=third consecutive even integer.


We're also going to assume that all of these integers are positive. So the third is the largest.



Since "three times the greatest of three consecutive even integers exceed twice the least by 38", we get the translation {{{3(x+4)=2x+38}}}




{{{3(x+4)=2x+38}}} Start with the given equation.



{{{3x+12=2x+38}}} Distribute.



{{{3x=2x+38-12}}} Subtract {{{12}}} from both sides.



{{{3x-2x=38-12}}} Subtract {{{2x}}} from both sides.



{{{x=38-12}}} Combine like terms on the left side.



{{{x=26}}} Combine like terms on the right side.



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Answer:


So the solution is {{{x=26}}} which means that the first number is 26, the next number is 26+2=28, and the third is 26+4=30