Question 226268
The sum of four consecutive odd integers is 216 . Find the four integers


Step 1.  Let n be the first odd integer.


Step 2.  Let n+2, n+4, and n+6 be the next three consecutive odd integers


Step 3.  Then, n+n+2+n+4+n+6=216 since the sum of the four consecutive odd integers is 216.


Step 4.  Solving the equation in Step 4 yields the following steps


*[invoke explain_simplification "n+n+2+n+4+n+6=216" ]


With n=51, then n+2=53, n+4=55, and n+6=57.  Also 51+53+55+57=216 as a check...


Step 5.  The four consecutive odd integers are  51, 53, 55, and 57



I hope the above steps were helpful. 


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Respectfully,
Dr J


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